# A ball of mass m is attached to one end of a light rod

**One**might wonder how you could easily

**mass**just the rim and tire.... (Table of contents) 38.A small 1.05kg

**ball**on the

**end**

**of**the

**light**

**rod**

**is**rotated in a horizontal circle of a radius 0.900

**m**. ... (i.e., we ignore friction) about a hinge

**attached**

**to**

**a**wall, as in Fig. 8-50. The

**rod**

**is**held horizontally and then released. At this moment of.

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**A ball of mass m**is

**attached to one end of a light rod**of length 1, the other end of which is hinged. What minimum velocity v should be imparted to

**the ball**downwards, so that it can complete

**the circle.**(a) Vge (c) /3g! (b) 5ge (d) V2gé..

**rod**of length 20 cm pivoted near an

**end**and which is made to rotate in a horizontal plane with a constant angular speed.

**A ball**

**of mass**

**m**is suspended by a string also of length 20 cm from the other

**end**of the

**rod**. If the angle θ made by the string with the vertical is 30, find the angular speed of the rotation. Take g=10m/s 2 ....

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**A**

**rod**

**of**length L and

**mass**

**M**has a nonuniform

**mass**distribution. The linear

**mass**density (

**mass**per length) is λ=cx2, where x is measured from the center of the

**rod**and c is a constant. Find the expression for c. Find the expression for the moment of inertia of the

**rod**for rotation about an axis through the center.

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**ball**

**is attached**

**to one**

**end**

**of a light**

**rod**that is 1.2

**m**long. The other

**end**of the

**rod**is loosely pinned at a frictionless pivot. The

**rod**is raised until it is vertical, with the

**ball**above the pivot. The

**rod**is released and the

**ball**moves in a vertical circle. The tension in the

**rod**as the

**ball**moves through the bottom of the circle ....